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Question

A pipet delivers $$9.98 \ g$$ of water at $$20^\circ C$$. What volume does the pipe deliver?

Solution
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The volume can be found out by $$\rho = \dfrac{m}{V}$$
Where, the density of water at $$20^o \ C$$ is $$0.998 \ gm/cm^3$$

$$\therefore V = \dfrac{9.98 \ g}{0.998 \ g/cm^3} = 10 \ cm^3 = 10 \ mL$$

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