△ABC and
△DBC are two isosceles triangles on the same base
BC and vertices
A and
D are on the same side of
BC. If
AD is extended to intersect
BC at
P, show that
(i)
△ABD≅△ACD(ii)
△ABP≅△ACP(iii)
AP bisects
∠A as well as
△D.
(iv)
AP is the perpendicular bisector of
BC.