An electron of charge 'e' and mass 'm' is accelerated from rest by a potential difference 'V'. The de Broglie wavelength is
Directly proportional to the square root of potential difference.
Inversely proportional to the square root of potential difference
Directly proportional to the square root of electron mass
Inversely proportional to the cube root of electron mass
A
Inversely proportional to the square root of potential difference
B
Directly proportional to the square root of potential difference.
C
Directly proportional to the square root of electron mass
D
Inversely proportional to the cube root of electron mass
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Solution
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12mv2=eV mv=√2eVm So de-broglie wavelength λ=hmv =h√2meV ∴λα1√V
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