At a given temperature $$T$$, gases $$Ne, Ar, Xe$$ and $$Kr$$ are found to deviate from ideal gas behaviour. Their equation of state is given as $$p = \dfrac {RT}{V - b}$$ at $$T$$.
Here, $$b$$ is the van der Waals constant. Which gas will exihibit steepest increase in the plot of $$Z$$ (compression factor) vs $$p$$?
Correct option is C. $$Xe$$
$$Z= 1 + \dfrac{b}{RT}P$$
$$Y=mX+C$$
As $$b\uparrow\ \Rightarrow slope \downarrow$$
We know that the 'b' is the volume occupied by the particles of the gas.
Xe has the highest size so it occupies the highest volume for a certain amount of gases.
Hence, $$Xe$$ will have the highest slope.