nOtHnHtO=√MHMO
nO12=√232
∵tO=tH and nH=12
nO=12×14=18
The fraction of the oxygen that escapes in the time required for one-half of the hydrogen to escape is 18
Note: Here nO represents the number of moles of oxygen effused in time tO and MO is the molar mass of oxygen.
Similarly, nH represents the number of moles of hydrogen effused in time tH and MH is the molar mass of hydrogen.