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Standard XI
Mathematics
NCERT
Question
Evaluate the given limit:
lim
x
→
0
(
x
+
1
)
5
−
1
x
Open in App
Solution
Verified by Toppr
lim
x
→
0
(
x
+
1
)
5
−
1
x
Put
x
+
1
=
y
So,
y
→
1
as
x
→
0
=
lim
y
→
1
y
5
−
1
5
y
−
1
=
5
⋅
1
5
−
1
[
lim
x
→
a
x
n
−
a
n
x
−
a
=
n
a
n
−
1
]
=
5
∴
lim
x
→
0
(
x
+
5
)
5
−
1
x
=
5
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