Find the values of x, which satisfy the inequation −256<12−2x3≤2,x∈W.
Given: −256<12−2x3≤2
⇒−176<3−4x6≤2
Multiplying throughout by 6
⇒−17<3−4x≤12
−17<3−4x and 3−4x≤12
⇒4x<3+17 ⇒3−12≤4x
⇒4x<20 ⇒−9≤4x
⇒x<5 ⇒−94<x
{5>x≥−94}
Hence, the solution set is {x:x∈W,−94≤x<5}
Since x is a whole number,
∴ Values of x are {0,1,2,3,4}