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Standard XI
Physics
Dimensions and Dimensional Analysis
Question
If C be the capacitance and V be the electric potential,then the dimensional formula of $$ CV^2 $$ is
A
$$ [ML ^{-3} TA] $$
B
$$ [ML ^1 A^{-1 }] $$
C
$$ [ML^2T^{-2} A^o] $$
D
$$ [M^oLT^{-2} A^o] $$
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Solution
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Correct option is D. $$ [ML^2T^{-2} A^o] $$
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