If x,y,z are in A.P. and A.M. of x and y is a and that to y and z is b, then A.M. of a and b is.
x
y
z
12(x+y)
A
x
B
12(x+y)
C
y
D
z
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Solution
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Given x,y,z are in A.P ⇒2y=x+z ′a′ is A.M of ′x′ and ′y′⇒a=x+y2 and ′b′ is A.M of ′y′ and ′z′⇒b=y+z2 ∴ A.M of a and b is =a+b2=x+2y+z4=y Hence, option 'B' is correct.
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