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Standard XII
Physics
Matter Waves
Question
Light of wavelength
500
n
m
is incident on a metal with a work function
2.28
e
V
. The de Borglie wavelength of the emitted electron is:
<
2.8
×
10
−
9
m
≤
2.8
×
10
−
12
m
≥
2.8
×
10
−
9
m
<
2.8
×
10
−
10
m
A
<
2.8
×
10
−
10
m
B
≥
2.8
×
10
−
9
m
C
≤
2.8
×
10
−
12
m
D
<
2.8
×
10
−
9
m
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Solution
Verified by Toppr
Energy of the photon:
E
=
12400
5000
=
2.48
e
V
Work function:
ϕ
=
2.28
e
V
K
E
m
a
x
=
E
−
ϕ
=
2.48
−
2.28
=
0.2
e
V
For electron,
λ
m
i
n
=
h
√
2
m
(
K
E
)
m
a
x
=
28
A
0
Hence,
λ
>
28
A
0
=
2.8
×
10
−
9
m
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Similar Questions
Q1
Light of wavelength
500
n
m
is incident on a metal with a work function of
2
.
28
e
V
. The de borglie wavelength of the emitted electron is