The displacement of a particle is given by x=(t−2)2 where x is in metres and t is in seconds. The distance covered by the particle in first 4 seconds is
8 m
4 m
12 m
16 m
A
4 m
B
8 m
C
12 m
D
16 m
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Solution
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The distance travelled is given by x=(t−2)2=t2–4t+4
As velocity is given by v=dxdt
v=2t−4
Distancecovered=∫|v|dt
=|t2–4t|
=4t−t2fort=0to2
=t2−4tfort=2to4
=8units
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