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Standard XII
Chemistry
Question
The number of radial nodes and angular nodes for d-orbital can be represented as:
(n-3) radial nodes + 2 angular node = (n-l-1) total nodes
(n-2) radial nodes + 1 angular node = (n-1) total nodes
(n-1) radial nodes + 1 angular node = (n-1) total nodes
(n-3) radial nodes + 2 angular node = (n-1) total nodes
A
(n-2) radial nodes + 1 angular node = (n-1) total nodes
B
(n-1) radial nodes + 1 angular node = (n-1) total nodes
C
(n-3) radial nodes + 2 angular node = (n-1) total nodes
D
(n-3) radial nodes + 2 angular node = (n-l-1) total nodes
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Solution
Verified by Toppr
Number of radial nodes
=
n
−
l
−
1
Number of a
ngular nodes
=
l
∴
Total number of nodes
=
n
−
l
−
1
+
l
=
n
−
1
For d-orbital,
l
=
2
,
thus number of radial nodes
=
n
−
2
−
1
=
n
−
3
and number of angular nodes
=
l
=
2
Total nodes
=
n
−
1
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