Two wires A and B of the same material, having radii in the ratio 1:2 and carry currents in the ratio 4:1. The ratio of drift speed of electrons in A and B is
16:1
4:1
1:4
1:16
A
1:16
B
1:4
C
16:1
D
4:1
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Solution
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Current flowing through the conductor, I=nevA.
Hence 41=nevd1π(1)2nevd2(2)2
or
vd1vd2=4×41=161
Hence correct answer is option A.
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