There are 5 black and 6 red balls in the bag.
2 black balls can be selected out of 5 black ball in 5C2 ways and 3 red ball can be selected out of 6 red balls in 6C3 ways.
Thus, by multiplication principle, required number of ways of selecting 2 black and 3 red balls is 5C2×6C3
=5!2!3!×6!3!3!
=5×42×6×5×43×2×1=10×20=200