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Standard XII
Physics
Question
A force of
10
N
acts on a body of mass
20
k
g
for
10
s
.Change in its momentum is:
5
k
g
m
/
s
100
k
g
m
/
s
200
k
g
m
/
s
1000
k
g
m
/
s
A
5
k
g
m
/
s
B
1000
k
g
m
/
s
C
100
k
g
m
/
s
D
200
k
g
m
/
s
Open in App
Solution
Verified by Toppr
Δ
P
=
F
Δ
t
=
10
×
10
=
100
k
g
m
/
s
Where,
Δ
P = Change in momentum,
F = Applied force
Δ
t = time for which force has been applied on the body
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