A parallel plate capacitor has plate area A and separation d. It is charged to a potential difference V0. The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is:
3ϵ0AV20d
ϵ0AV202d
ϵ0AV20d
ϵ0AV203d
A
ϵ0AV203d
B
ϵ0AV20d
C
3ϵ0AV20d
D
ϵ0AV202d
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Solution
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Here, W=Uf−Ui
where, Ui=12CV20
Uf=1.C.(3V0)22.3
=3∗12CV0
So, W=ϵ0AV20d
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