Find the area of rhombus if its vertices are (3,0),(4,5),(−1,4) and (−2,−1) taken in order.
[Hint: Area of rhombus =12× product of its diagonals.]
Open in App
Solution
Verified by Toppr
We know that,
Area of Rhombus =12 (Product of its diagonals)
Given co-ordinates of rhombus are (3,0),(4,5),(−1,4) and (−2,−1)
Diagonal 1=√(3+1)2+(0−4)2=4√2
Diagonal 2=√(4+2)2+(5+1)2=6√2
∴ Area of rhombus =12(4√2×6√2)
=24 unit2
Was this answer helpful?
6
Similar Questions
Q1
Find the area of rhombus if its vertices are (3,0),(4,5),(−1,4) and (−2,−1) taken in order.
[Hint: Area of rhombus =12× product of its diagonals.]
View Solution
Q2
Question 10 Find the area of a rhombus if its vertices are (3, 0), (4, 5), (-1, 4) and (-2,-1) taken in order. [Hint: Area of a rhombus = 12(product of its diagonals)]
View Solution
Q3
Find the area of rhombus if its vertices are (3,0), (4,5), (-1,4), (-2,-1) taken in order
View Solution
Q4
Prove that the points (3, 0), (4, 5), (−1, 4) and (−2 −1), taken in order, form a rhombus. Also, find its area.