If the radius of the base is doubled, keeping the height constant, what is the ratio of the volume of the large cone to the smaller cone?
4:1
3:1
8:1
None of these
A
8:1
B
3:1
C
None of these
D
4:1
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Solution
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Here, r2=2r1 & h1=h2.
We know, volume of cone V=13πr2h.
Then, the ratio of volume,
V2V1=π3r22h2π3r21h1
V2V1=π3(2r1)2h1π3r21h1
⇒V2:V1=4:1 .
Hence, option A is correct.
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