If bc:ac:ab=1:3:5, then find abc:bca.
Given:
bc:ac:ab=1:3:5
Let say →bc=x ; ac=3x ; ab=5x
If we multiply all then -
bc×ac×ab=(x)(3x)(5x)
a2b2c2=15x3
abc=x√15x ___ (i)
∵bc=x; so, a(x)=x√15x⇒a=√15x
similarly ∵ac=3x;
abc=x√15x
b(ac)=x√15x
b(3x)=x√15x⇒b=13√15x
Ratio :
⇒abc:bca
⇒√15xx:13√15x3x⇒11:13×3⇒1:19
⇒9:1 Answer