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Question
In Figure 3.11 , line AB \( \| \) line CD and line \( P Q \) is the transversal. Ray \( P T \) and ray QTare bisectors of \( \angle \mathrm { BPQ } \) and \( \angle P Q D \) respectively Prove that \( \mathrm { m } \angle \mathrm { PTQ } = 90 ^ { \circ } \) \( A \) \( i Q \)
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Q1
In the given Figure, line AB || line CD and line PQ is the transversal. Ray PT and ray QT are bisectors of BPQ and PQD respectively.
Prove that m PTQ = 90 °.