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Standard XII
Physics
Dimensional Analysis
Question
The dimension of
(
1
2
)
ε
0
E
2
is(
ε
0
: permittivity of free space, Electric field)
M
L
−
1
T
−
2
M
L
2
T
−
1
M
L
T
−
1
M
L
2
T
−
2
A
M
L
2
T
−
1
B
M
L
T
−
1
C
M
L
−
1
T
−
2
D
M
L
2
T
−
2
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Solution
Verified by Toppr
As we know that
Energy Density
=
e
n
e
r
g
y
v
o
l
u
m
e
=
(
1
2
)
ε
0
E
2
Hence ,
Dimesion of
(
1
2
)
ε
0
E
2
is, =
[
M
L
2
T
−
2
]
L
3
=
M
L
−
1
T
−
2
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