The graph between the stopping potential V0 and frequency v for two different metal plates P and Q are shown in the figure. Which of the metals has greater threshold wavelength and work function?
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Solution
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The threshold frequency of metal plate P is lesser than that of Q.
Since λ∝1ν, the threshold wavelength of metal plate P is greater than that of Q.
The work function of a metal is given as
W0=hν0
Since the threshold frequency of metal Q is greater, the work function it is also greater than that of P.
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