The molecules of a given mass of a gas have r.m.s velocity of 200ms−1 at 270C and 1.0×105Nm−2 pressure. When the temperature and pressure of the gas are respectively, 1270C and 0.05×105Nm−2, the r.m.s. velocity of its molecules in ms−1 is:
100√2
400√3
100√23
1003
A
100√2
B
100√23
C
400√3
D
1003
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Solution
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We know that: v∝√T
⇒v200=√400300
⇒v=200×2√3=400√3m/s
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