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Standard XII
Physics
Question
The output
Y
of the logic circuit given above is:
¯
A
+
B
¯
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
¯
(
¯
A
+
B
)
⋅
A
¯
A
¯
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
¯
(
¯
A
+
B
)
⋅
¯
A
A
¯
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
¯
(
¯
A
+
B
)
⋅
A
B
¯
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
¯
(
¯
A
+
B
)
⋅
¯
A
C
¯
A
+
B
D
¯
A
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Solution
Verified by Toppr
Using the Boolean expression, we write the output for each logic gate as shown.
The output of signal
A
after passing through
N
O
T
gate is
¯
A
The output of signals
¯
A
and
B
after passing through
A
N
D
gate is
¯
A
.
B
The output of signals
¯
A
.
B
and
¯
A
after passing through
O
R
gate is
¯
A
+
¯
A
.
B
Thus the output signal of the logic circuit
Y
=
¯
A
+
¯
A
.
B
∴
Y
=
¯
A
(
1
+
B
)
Using
1
+
B
=
1
, we get
Y
=
¯
A
.1
⟹
Y
=
¯
A
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3
Similar Questions
Q1
If
¯
a
,
¯
b
and
¯
c
are perpendicular to
¯
b
+
¯
c
,
¯
c
+
¯
a
and
¯
a
+
¯
b
respectively and If
∣
∣
¯
a
+
¯
b
∣
∣
=
6
,
∣
∣
¯
b
+
¯
c
∣
∣
=
8
and
|
¯
c
+
¯
a
|
=
10
, then
∣
∣
¯
a
+
¯
b
+
¯
c
∣
∣
is equal to
View Solution
Q2
If
(
¯
A
+
¯
B
)
is perpendicular to
¯
B
and If
(
¯
A
+
2
¯
B
)
is perpendicular to
¯
A
, then
View Solution
Q3
Let
¯
a
,
¯
b
be unit vectors,
¯
a
⊥
¯
b
If
¯
r
is a vector such that
|
¯
r
|
=
2
,
(
¯
a
,
¯
r
)
=
π
3
and
(
¯
a
×
¯
b
)
×
(
¯
a
×
¯
r
)
=
¯
a
Then
(
¯
b
,
¯
r
)
=
View Solution
Q4
¯
a
,
¯
b
such that
|
¯
a
|
=
√
3
,
∣
∣
¯
b
∣
∣
=
2
and
(
¯
a
,
b
)
=
π
3
then the area of the triangle with adjacent sides
¯
a
+
2
¯
b
and
2
¯
a
+
¯
b
is
View Solution
Q5
If
¯
a
and
¯
b
are unit vectors such that
∣
∣
¯
a
×
¯
b
∣
∣
=
1
,
then the angle between
¯
a
and
¯
b
is
View Solution