The oxidation number of sulphur in sodium thiosulphate is-1024

Question

Toppr Admin · Accepted Answer

-xA0- -xA0- -xA0- -xA0- xNa2S2O3-2-2x-x2212-6-0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0- 2x-4-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0-xA0- -xA0- -xA0- x-2 Thus oxidation state of -apos-S-apos- in sodium thiosulphate is -2

The oxidation number of sulphur in sodium thiosulphate is:
1
0
2
4

$x$
$N a_{2} S_{2} O_{3}$
$+ 2 + 2 x - 6 = 0$
$2 x = 4$
$x = + 2$ Thus oxidation state of 'S' in sodium thiosulphate is +2

The oxidation number of sulphur in sodium thiosulphate is:1024

xNa2S2O3+2+2x−6=0 2x=4 x=+2 Thus oxidation state of 'S' in sodium thiosulphate is +2

The oxidation number of sulphur in sodium thiosulphate is:
1
0
2
4

$x$
$N a_{2} S_{2} O_{3}$
$+ 2 + 2 x - 6 = 0$
$2 x = 4$
$x = + 2$ Thus oxidation state of 'S' in sodium thiosulphate is +2