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Question

Two identical spherical masses are kept at some distance as shown. Potential energy when a mass m is taken from the surface of one sphere to the other
5484.png
  1. decreases continuously
  2. increases continuously
  3. first increases, then decreases
  4. first decreases, then increases

A
first increases, then decreases
B
decreases continuously
C
first decreases, then increases
D
increases continuously
Solution
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Gravitational potential energy between two masses (M) separated by a distance R is GMM/R=GM2/R.

When a small mass m is taken out of mass M, and kept at a distance x from (M-m), the total PE of the system becomes GMm/(Rx)Gm(Mm)/xGM(Mm)/R

As m moves towards M, the gravitational PE in the system will increase. Mass (M-m) will attract mass m and external for will be required to move m away from (M-m).

Once mass m reaches a point P where R1 is the distance between mass m and M and R2 is the distance between m and (M-m) and R1 and R2 related as R1/R2=M/(Mm), the potential energy on mass m will be zero. At this point mass m will not experience any force.

As mass m stars moving towards mass M, the PE will decrease as mass M will attract mass m.

So, in this situation, PE of the total system will increase first and then decrease.


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