Two wheels of M-I- 3kg - m - 2 - and 5kg - m - 2 - are rotating the rate of 600 rpm and 800 rpm respectively in the same direction- If the two are coupled so as to rotate with the same axis of rotation- the resultant speed of rotation will be -in rpm-725850420630

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Toppr Admin · Accepted Answer

By conservation of angular momentumI-x3C9-I1-x3C9-1-I2-x3C9-2-3-5-x3C9-3-xD7-600-5-xD7-800-5800-x3C9-725rpm

Two wheels of $M . I . 3 k g m^{2}$ and $5 k g m^{2}$ are rotating at the rate of $600 r p m$ and $800 r p m$ respectively in the same direction. If the two are coupled so as to rotate with the same axis of rotation, the resultant speed of rotation will be (in $r p m$ )
$725$
$850$
$420$
$630$

by conservation of angular momentum
$I ω = I_{1} ω_{1} + I_{2} ω_{2}$
$(3 + 5) ω = 3 \times 600 + 5 \times 800 = 5800$
$ω = 725 r p m$

Two wheels of M.I.3kg m2 and 5kg m2 are rotating at the rate of 600 rpm and 800 rpm respectively in the same direction. If the two are coupled so as to rotate with the same axis of rotation, the resultant speed of rotation will be (in rpm)725850420630

by conservation of angular momentumIω=I1ω1+I2ω2(3+5)ω=3×600+5×800=5800ω=725rpm

Two wheels of $M . I . 3 k g m^{2}$ and $5 k g m^{2}$ are rotating at the rate of $600 r p m$ and $800 r p m$ respectively in the same direction. If the two are coupled so as to rotate with the same axis of rotation, the resultant speed of rotation will be (in $r p m$ )
$725$
$850$
$420$
$630$

by conservation of angular momentum
$I ω = I_{1} ω_{1} + I_{2} ω_{2}$
$(3 + 5) ω = 3 \times 600 + 5 \times 800 = 5800$
$ω = 725 r p m$