A particle X moving with a certain velocity has a de-Broglie wavelength of 1A0. If particle Y has a mass of 25 % that of X and velocity 75% that of X, de Broglie's wavelength of Y will be:
3Ao
5.33Ao
6.880Ao
48Ao
A
5.33Ao
B
6.880Ao
C
3Ao
D
48Ao
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Solution
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According to question,
mY=mX×25100=0.25mX
and vY=vX×75100=0.75vX
De brogile wavelength λ=hmv
λX=1A0=hmX×vX
λY=h(0.25mX×0.75vX)=5.33hmX×vX=5.33A0
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