An electron enters into a space between the plates of a parallel plate capacitor at an angle αwith the plates and leaves at an angle βto the plates. The ratio of its kinetic energy while entering the capacitor to that while leaving it, will be :
(cosβcosα)2
(cosαcosβ)2
(sinαsinβ)2
(sinβsinα)2
A
(cosαcosβ)2
B
(sinαsinβ)2
C
(cosβcosα)2
D
(sinβsinα)2
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Solution
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The velocity of electron in x direction must not change as force is being applied in y direction only. ∴V1cosα=V2cosB (x direction velocities must be same). ⇒V2=V1cosαcosB initial kinetic energy (E1)=12meV21 final kinetic energy (E2)=12me(V1cosαcosB)2. ∴E2E1=(cosBcosα)2.
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