At −50∘C, liquid NH3 has ionic product is 10−30. How many amide (NH−2) ions are present per mm3 is pure liquid NH3? (Take NA=6×1023).
500 ions
602.2 ions
222.2 ions
22 ions
A
602.2 ions
B
22 ions
C
500 ions
D
222.2 ions
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Solution
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ionic product of NH3=KNH3=[NH+4][NH−2]=10−30
[NH−2]=√10−30=10−15M
Since, 1L contains 10−15 moles
∴1mm3 will contain 10−15/106 moles=10−21 moles
number of NH2− ins=6.022×1023×10−21=602.0 ions.
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Q1
At −50∘C, liquid NH3 has ionic product is 10−30. How many amide (NH−2) ions are present per mm3 is pure liquid NH3? (Take NA=6×1023).
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Q2
At 50C, liquid NH3 has ionic product is 10−30. How many amide (NH2−) ions are present per mm3 in pure liquid NH3 ? (take NA=6×1023)
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Q3
At 50oC, the self-ionisation constant (ionic product) of NH3 is given as, KNH3=[NH+4][NH−2]=10−30M2. How many NH−2 ions are present per mm3 of pure liquid ammonia?
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Q4
At 50oC, the self-ionisation constant (ionic product) of NH3 is given as, KNH3=[NH+4][NH−2]=10−30M2.
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Q5
Auto-ionisation of liquid NH3 is
2NH3⇌NH⊕4+NH⊝2
with KNH3=[NH⊕4][NH⊝2]=10−30at−50oC
Number of atomic ions (NH⊝2), present per mm3 of pure liquied NH3 is: