Complete the following reaction:
$$(CH_{3})_{3}CH+Br_{2}\xrightarrow[]{hv}(A)\xrightarrow[(ii)D_{2}O]{(i)Mg/ether}(B)$$
When alkane reacts with bromine in presence of light, alkyl bromide forms. Reaction of alkyl bromide with $$Mg/Ether$$ produces Grignard reagent. The reaction of Grignard reagent with $$D_2O$$ produces deuterium product.
$$(CH_3)_3CH+Br_2\overset{hv}{\rightarrow}(CH_3)_3CBr (A)\overset{(i)Mg/ether)}{\rightarrow}(CH_3)_3CMgBr\overset{(ii))D_2O}{\rightarrow}(CH_3)_3CD (B)$$