How much length of the iron sheet 11 cm wide is required for making an open cylinder 15 cm high and 7 cm as base radius (π=22/7)?
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Solution
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Surface of an open cylinder = area of the iron sheet =πr2+2πrh =227×72+2×227×7×15 =(154+660)cm2 =814cm2 ∴ Length of the sheet =(814÷11)cm =74cm
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