In the given figure P Q - R S - prove that Delta P O Q sim Delta SOR-

Question

In the given figure  P Q - R S - prove that  Delta P O Q sim Delta SOR-

Toppr Admin · Accepted Answer

-PQ - RS-160- -160- -160-Given-160-In - -Delta P O Q - and - -Delta S O R - -angle P O Q-angle S O R - -Vertically-160-opposite-160-angles- -angle P-angle S -160- -Alternate Angles- -angle Q-angle R -160- -Alternate Angles-160- -therefore -Delta P O Q -sim -Delta S O R -qquad-AAA-

In the given figure if $$ P Q \| R S $$, prove that $$ \Delta P O Q \sim \Delta SOR.$$

$$PQ || RS $$ (Given)
In $$ \Delta P O Q $$ and $$ \Delta S O R $$
$$ \angle P O Q=\angle S O R $$ [Vertically opposite angles]
$$ \angle P=\angle S $$ (Alternate Angles)
$$ \angle Q=\angle R $$ (Alternate Angles)
$$ \therefore \Delta P O Q \sim \Delta S O R \qquad$$(AAA)

In the given figure if $$ P Q \| R S $$, prove that $$ \Delta P O Q \sim \Delta SOR.$$

$$PQ || RS $$ (Given) In $$ \Delta P O Q $$ and $$ \Delta S O R $$$$ \angle P O Q=\angle S O R $$ [Vertically opposite angles]$$ \angle P=\angle S $$ (Alternate Angles)$$ \angle Q=\angle R $$ (Alternate Angles) $$ \therefore \Delta P O Q \sim \Delta S O R \qquad$$(AAA)

$$PQ || RS $$ (Given)
In $$ \Delta P O Q $$ and $$ \Delta S O R $$
$$ \angle P O Q=\angle S O R $$ [Vertically opposite angles]
$$ \angle P=\angle S $$ (Alternate Angles)
$$ \angle Q=\angle R $$ (Alternate Angles)
$$ \therefore \Delta P O Q \sim \Delta S O R \qquad$$(AAA)