Find whether f(x)=ax+1ax−1 is even, odd or neither odd nor even.
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Q4
Find out whether the given function is even, odd or neither even nor odd, where f(x)=⎧⎪⎨⎪⎩x|x|,x≤−1[1+x]+[1−x],−1<x<1−x|x|,x≥1 where || and [] represent the modulus and greatest integral functions.
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Q5
Assertion :f is even, g is odd then fg(g≠0) is an odd function. Reason: If f(−x)=−f(x) for every x of its domain then f(x) is called odd function and if f(−x)=f(x) for every x of its domain, then f(x) is called even function.