The correct option is C (i) → (b), (ii) → (c), (iii) → (a), (iv) → (d)
In fig (i), △ADB and △ADC
It is given that, AB=AC, ∠ADB=∠ADC=90o and AD=AD
∴ So, By RHS criteria $△ADB≅△ADC
In fig (ii), △BAD and △DCB
It is given that, BA=DC,AD=CB and BD=DB
∴ By SSS criteria △BAD≅△DCB
In fig (iii), △ABC and △CDA
AB∥CD and BC∥DA
∠BAC=∠DCA and ∠BCA=∠DAC [Alternate angles between parallel lines]
AC=CA [Common side]
∴ △ABC≅△CDA, by ASA criteria.
In fig (iv), △ABE and △DCE
It is given that, AB=DC,∠A=∠D and AE=DE
∴ △ABE≅△DCE, by SAS criteria.
∴ Correct answer is option C.