The measurement of voltmeter in the following circuit is
2.4V
3.4V
4.0V
6.0V
A
3.4V
B
4.0V
C
2.4V
D
6.0V
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Solution
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Resistance of voltmeter and 60Ω are in parallel. ∴ Equivalent resistance =60×4060+40=60×40100=24Ω For the whole circuit, current I=6V(40+24)Ω=664=332A The voltmeter reads potential difference across 60Ω. ∴ Voltmeter reading =I×Req =332×24=94V=2.25V.
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