A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
T4
T8
T12
T2
A
T4
B
T8
C
T2
D
T12
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Solution
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The correct option is CT12 Equation of a SHM is given by X=Asin(ωt)
Here ω=2πT
Time to travel half of the amplitude
A2=Asin(ωt)
⇒ωt=π6
⇒t=T12
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