If a 3cm tall object placed perpendicular to principal axis of a convex lens of focal length 15cm produces a real invented image of height 15cm, then its object distance (u) is ................ and image distance (v) is ................
u=−18m,v=+90m
u=−18cm,V=+90cm
y=+18cm,v=+90cm
u=+18cm,v=−90cm
A
u=−18cm,V=+90cm
B
u=−18m,v=+90m
C
u=+18cm,v=−90cm
D
y=+18cm,v=+90cm
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Solution
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h1=3cm h2=15cm m=h2h1=153=5 As image is real and inverted m=−5 object distance is always negative ∴u=−18cm and v=+90cm
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