The potential energy of a particle of mass 10g varies as its displacement from its mean position given by U=3x2+3, then, the particle performs a
SHM with time period T=π s
Linear motion
SHM with time period T=π5√6 s
SHM with time period T=π/5 s
A
Linear motion
B
SHM with time period T=π s
C
SHM with time period T=π5√6 s
D
SHM with time period T=π/5 s
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Solution
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The force acting on the system is F=−dU/dx=−6x⟹a=−(6/0.01)x=−600x. The angular velocity of the particle is ω=√600
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