The purple color in KMnO4 arises from an electronic transition, but it is actually not a d-d transition, since the Mn in this compound has no d electrons. It arises from a charge transfer reaction within the molecule, in which photons promote an electron from the highest energy molecular orbital in one of the Mn-O bonds to an empty d orbital on the manganese.
Charge transfer from the ligand(O2–) to the metal center. This is called a ligand-to-metal charge transfer.
Hence,option C is correct.
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Q1
The purple color of KMnO4 is due to:
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Q2
Assertion :KMnO4 is purple in colour due to charge transfer. Reason: There is no electron present in d−orbitals of manganese in MnO−4 .
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Q3
Assertion :KMnO4 is reduced to Mn2+. Reason: Reacting the suspected reducing agent with potassium tetraoxomanganate (VII) solution, KMnO4 (purple color), and the color is observed to become colorless Mn2+.