A 9V battery is connected to four resistor to form a simple circuit as shown in figure. How would the current through the 2Ω resistor compare to the current through the 4Ω-ohm resistor?
One−fourth
One−half
Fourtimes
Equal
A
One−half
B
Fourtimes
C
Equal
D
One−fourth
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Solution
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Req=(7+2)//(4+5)=9//9=9×99+9=8118=4.5Ω
Current(I)=VR=94.5=2A
As both branch having equal resistance current will flow same in both branch
Therefore current flow in 7Ω is 22=1A
So equal current will follow in both resistance.
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