Quadrilateral ABCD is a square. X is the mid-point of AB and Y is the mid-point of BC. Hence, ∠DXA=∠AYB
If the above statement is true then mention answer as 1, else mention 0 if false
Open in App
Solution
Verified by Toppr
AB=BC (ABCD is a square)
12AB=12BC
AX=BY (X and Y are mid points of AB and BC respectively)
In △AXD and △ABY,
∠DAX=∠ABY (Each 90∘)
AX=BY (Proved above)
AD=AB (ABCD is a square)
Thus, △AXD≅△BYA
Hence, ∠DXA=∠AYB (By cpct)
Was this answer helpful?
0
Similar Questions
Q1
Quadrilateral ABCD is a square. X is the mid-point of AB and Y is the mid-point of BC. Hence, ∠DXA=∠AYB
If the above statement is true then mention answer as 1, else mention 0 if false
View Solution
Q2
ABCD is a square; X is the mid-point of AB and Y the mid-point of BC . Hence, The triangles ADX and BAY are congruent If the above statement is true then mention answer as 1, else mention 0 if false
View Solution
Q3
ABCD is a square; X is the mid-point of AB and Y the mid-point of BC.Hence, DX is perpendicular to AY.
If the above statement is true then mention answer as 1, else mention 0 if false.
View Solution
Q4
From the given diagram, in which ABCD is a parallelogram, ABL is a line segment and E is mid point of BC. Hence, $AB = BL.$
If the above statement is true then mention answer as 1, else mention 0 if false
View Solution
Q5
The perpendiculars from the mid-point of BC to AB and AC are equal.
If the above statement is true then mention answer as 1, else mention 0 if false.