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Standard VI
Mathematics
Equivalent Fractions
Question
2
3
=
2
2
2
−
1
;
1
2
−
1
4
=
2
8
=
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Solution
Verified by Toppr
2
3
=
2
2
2
−
1
=
2
3
1
2
−
1
4
=
4
−
2
8
=
2
8
=
1
4
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View Solution
Q3
Find the value of.
(i) (3
0
+ 4
−1
) × 2
2
(ii) (2
−1
× 4
−1
) ÷2
−2
(iii)
(iv) (3
−1
+ 4
−1
+ 5
−1
)
0
(v)