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Standard XII
Mathematics
Question
cos
θ
√
1
+
cot
2
θ
=
tan
θ
cot
θ
=
sin
θ
=
cos
θ
A
tan
θ
B
cos
θ
C
cot
θ
=
D
sin
θ
=
Open in App
Solution
Verified by Toppr
Use 1 +
cot
2
θ
=
c
o
s
e
c
2
θ
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Similar Questions
Q1
cos θ/(1 - tan θ) + sin θ/(1 - cot θ) = sin θ + cos θ
View Solution
Q2
Prove that
sin
θ
−
cos
θ
+
1
sin
θ
+
cos
θ
−
1
=
1
sec
θ
−
tan
θ
, using the identity
sec
2
θ
=
1
+
tan
2
θ
.
View Solution
Q3
Prove the following.
(1) secθ (1 – sinθ) (secθ + tanθ) = 1
(2) (secθ + tanθ) (1 – sinθ) = cosθ
(3) sec
2
θ + cosec
2
θ = sec
2
θ × cosec
2
θ
(4) cot
2
θ – tan
2
θ = cosec
2
θ – sec
2
θ
(5) tan
4
θ + tan
2
θ = sec
4
θ – sec
2
θ
(6)
1
1
-
sin
θ
+
1
1
+
sin
θ
=
2
sec
2
θ
(7) sec
6
x
– tan
6
x
= 1 + 3sec
2
x
× tan
2
x
(8)
tan
θ
s
e
c
θ
+
1
=
s
e
c
θ
-
1
tan
θ
(9)
tan
3
θ
-
1
tan
θ
-
1
=
sec
2
θ
+
tan
θ
(10)
sin
θ
-
cos
θ
+
1
sin
θ
+
cos
θ
-
1
=
1
sin
θ
-
tan
θ
View Solution