What will be the E0 value for the given half cell reaction? Cr2+(aq)+2e−→Cr(s)
Given: E0 value for the half cell reaction, Cr3+(aq)+e−→Cr2+(aq);E0=−0.41V Cr3+(aq)+3e−→Cr(s);E0=−0.74V
View Solution
Q4
The value of E for elements are as follows: Fe+2+2e→Fe;Eo=0.44V Fe+3+1e→Fe+2;Eo=+0.77V Sn+4+2e→Sn+2;Eo=+0.13V I2+2e→2I;Eo=+0.54V Cr3++3e→Cr;Eo=0.74V Based on the above data correct statements are:
View Solution
Q5
The standard reduction potentials for the following reaction are Zn2++2e−→Zn;(−0.762V) Cr3++3e−→Cr;(−0.74V) 2H++2e−→H2;(0.0V) Fe3++e−→Fe2+;(0.77V) The reducing powers of these species are in the order: