If $$m$$ compound microscope $$m_{1}$$ and $$m_{2}$$ be the linear magnification of the objective lens and eye lens respectively, then magnifying power of the compound microscope will be
A
$$\sqrt {m_{1} + m_{2}}$$
B
$$(m_{1} + m_{2})/2$$
C
$$m_{1}\times m_{2}$$
D
$$m_{1} - m_{2}$$
Open in App
Solution
Verified by Toppr
Correct option is D. $$m_{1}\times m_{2}$$ Magnification of a compound microscope is given by $$m=-\dfrac{v_0}{u_0}\times \dfrac{D}{u_e}\Rightarrow | m| =m_0 \times m_e$$
Was this answer helpful?
3
Similar Questions
Q1
If $$m$$ compound microscope $$m_{1}$$ and $$m_{2}$$ be the linear magnification of the objective lens and eye lens respectively, then magnifying power of the compound microscope will be
View Solution
Q2
magnification and magnifying power is same thing then why magnification of eye lens or objective lens is used and magnifying power of compound microscope and simple microscope is used is reverse term possible i.e. magnification of simple microscope and compound microscope similarly magnifying power of eye lens or objective lens
View Solution
Q3
The magnification produced by the objective lens and the eye of a compound microscope are $$25$$ and $$6$$ respectively. The magnifying power of this microscope is
View Solution
Q4
The transverse magnification produced by the objective lens and the angular magnification of the eye-lens of a compound microscope are 25 and 6, respectively. The magnifying power of this microscope is
View Solution
Q5
The magnifying power of the objective and eye-piece of a compound microscope are m1 and m2 . The magnifying power of microscope will be __________.