If the work function of a potential is 6.875eV, its threshold wavelength will be (Take =c=3×103m/s).
3600oA
1800oA
2400oA
1200oA
A
2400oA
B
1800oA
C
1200oA
D
3600oA
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Solution
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The correct option is C1800oA W=hcλ where h is planck's constant, c is speed of light, λ is wavelength λ=hcW=6.6×10−34×3×1086.825×1.6×10−19 λ=1800oA.
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