In a hot water heating system, there is a cylindrical pipe of length 28m and diameter 5cm. Find the total radiating surface in the system.
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Solution
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Given:
H=28m, R=52=2.5cm =0.025m (2.5100)
⇒CSA of pipe (cylindrical)=2πrh
=2×227×0.025×28m2
=4.4m2
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