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Standard XI
Mathematics
NCERT
Question
Prove the following:
cos
(
3
π
2
+
x
)
cos
(
2
π
+
x
)
[
cot
(
3
π
2
−
x
)
+
cot
(
2
π
+
x
)
]
=
1
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Solution
Verified by Toppr
L
H
S
=
c
o
s
(
3
π
2
+
x
)
c
o
s
(
2
π
+
x
)
[
c
o
t
(
3
π
2
−
x
)
+
c
o
t
(
2
π
+
x
)
]
=
sin
x
cos
x
[
tan
x
+
cot
x
]
=
sin
x
cos
x
(
sin
2
x
+
cos
2
x
)
sin
x
cos
x
=
1
=
R
H
S
Hence proved
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Prove the following:
cos
(
3
π
2
+
x
)
cos
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π
+
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[
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−
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)
+
cot
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]
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Q4
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π
2
+
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)
cos
(
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π
+
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)
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(
3
π
2
−
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)
+
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)
]
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