Some equipotential surface are shown in the figure. The magnitude and directions of the electric field is
100V/m making angle 120o with the x-axis
None of the above
200V/m making angle 120o with the x-axis
100V/m making angle 60o with the x-axis
A
100V/m making angle 120o with the x-axis
B
100V/m making angle 60o with the x-axis
C
None of the above
D
200V/m making angle 120o with the x-axis
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Solution
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Perpendicular distance between equipotential surfaces: d=10sin30o=5cm E=ΔVd=30−205/100=200Vm−1 Direction of electric field will be in the direction of decreasing potential
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